Roll Forming Hydraulic & Cutting Engineering (Part 7): Flying Shear Physics, Blade Metallurgy & Dynamic Load Control

Advanced guide to roll forming hydraulic systems, flying shear design, blade metallurgy, harmonic vibration & servo vs induction drives.

How a Roll Forming Machine Is Made — Part 7

Hydraulic System & Cutting Technology Engineering

(Flying Shear Physics, Blade Metallurgy & Dynamic Load Control)

Introduction — Where Continuous Motion Meets Instantaneous Force

Roll forming is continuous.

Cutting is instantaneous.

That transition is where most instability is introduced.

At the moment of cut:

• Strip tension changes
• Drive torque spikes
• Frame experiences shock load
• Hydraulic pressure peaks
• Torsional oscillation increases

Poorly engineered cutting systems cause:

• Length inaccuracy
• Profile deformation
• Gear wear
• Bearing fatigue
• Frame micro-movement
• Noise spikes

This section explains the physics and control behind cutting systems.

1. Hydraulic System Engineering Fundamentals

Hydraulic systems in roll forming power:

• Flying shears
• Stop-cut shears
• Punch presses
• Notching systems

A hydraulic system must provide:

• Adequate force
• Controlled speed
• Repeatable stroke
• Pressure stability
• Thermal control

1.1 Hydraulic Power Equation

Hydraulic power:

P=p×QP = p × QP=p×Q

Where:

• p = pressure (Pa)
• Q = flow rate (m³/s)

Power in kW:

P(kW)=p(bar)×Q(L/min)600P(kW) = \frac{p(bar) × Q(L/min)}{600}P(kW)=600p(bar)×Q(L/min)​

Example:

Pressure = 180 bar
Flow = 40 L/min

P=180×40600=12kWP = \frac{180 × 40}{600} = 12 kWP=600180×40​=12kW

Hydraulic motor must exceed this requirement.

2. Shear Force Calculation

Cutting force estimation:

F=τ×AF = \tau × AF=τ×A

Where:

• τ\tauτ = shear strength
• A = shear area

For mild steel:

Shear strength ≈ 0.8 × yield strength

Example PBR:

Yield = 350 MPa
Shear strength ≈ 280 MPa

Material thickness = 0.75 mm
Profile width = 914 mm

Shear area:

A=0.00075×0.914=0.0006855m2A = 0.00075 × 0.914 = 0.0006855 m²A=0.00075×0.914=0.0006855m2

Force:

F=280,000,000×0.0006855F = 280,000,000 × 0.0006855F=280,000,000×0.0006855

F≈191,940N≈192kNF ≈ 191,940 N ≈ 192 kNF≈191,940N≈192kN

Hydraulic cylinder must exceed 200 kN with safety margin.

3. Stop-Cut vs Flying Shear Engineering

Stop-Cut System

Process:

• Line stops
• Shear actuates
• Line restarts

Advantages:
• Simpler
• Lower cost

Disadvantages:
• Speed limitation
• Profile distortion at restart
• Production inefficiency

Flying Shear System

Process:

• Shear moves with strip
• Synchronizes speed
• Cuts while moving
• Returns

Advantages:
• Continuous production
• Higher speed
• No stop marks

Disadvantages:
• Complex motion control
• Higher cost
• Servo synchronization required

4. Flying Shear Motion Physics

Flying shear must:

  1. Accelerate to strip speed

  2. Match velocity

  3. Perform cut

  4. Decelerate

  5. Return

Motion equation:

v(t)=atv(t) = a tv(t)=at

If strip speed = 40 m/min = 0.666 m/s

If shear acceleration = 2 m/s²

Time to reach speed:

t=0.6662=0.333st = \frac{0.666}{2} = 0.333 st=20.666​=0.333s

Total cut window often < 1 second.

Control must be extremely precise.

5. Dynamic Load Transfer During Cutting

Cutting introduces shock load into frame.

Dynamic load multiplier:

Fdynamic=Fstatic×KdF_{dynamic} = F_{static} × K_dFdynamic​=Fstatic​×Kd​

Where KdK_dKd​ often 1.3–1.8 depending on blade geometry.

For 192 kN static:

Worst case dynamic:

192×1.5≈288kN192 × 1.5 ≈ 288 kN192×1.5≈288kN

Frame and shafts must absorb this.

6. Blade Metallurgy Engineering

Shear blades operate under:

• High compressive stress
• Impact loading
• Abrasion
• Micro-chipping risk

Common blade materials:

• D2
• H13
• SKD11
• Tungsten carbide inserts (high production lines)

6.1 Blade Hardness Targets

Roofing:

58–60 HRC

Heavy deck:

60–62 HRC

Too hard:

• Brittle fracture

Too soft:

• Rapid edge rounding

7. Blade Clearance Engineering

Proper blade clearance:

Clearance≈5–10Clearance ≈ 5–10% \text{ of material thickness}Clearance≈5–10

For 0.75 mm:

Clearance = 0.037–0.075 mm

Too tight:

• Burr
• Excess load

Too loose:

• Tearing
• Distorted edge

8. Servo vs Induction Motor Deep Comparison

Induction Motor + VFD

Advantages:
• Robust
• Cost effective
• Low maintenance

Disadvantages:
• Slower torque response
• Less precise position control
• Speed drift under rapid load change

Best for:
• Medium-speed lines
• Stop-cut systems

Servo Motor System

Advantages:
• Instant torque response
• High precision speed matching
• Better flying shear sync
• Reduced torsional oscillation

Disadvantages:
• Higher cost
• More complex control
• Requires tuning

Best for:
• Flying shear
• High-speed stud lines
• Punch integration

Torque Response Comparison

Induction motor torque response delay:

50–150 ms

Servo motor response:

< 10 ms

At 40 m/min:

In 100 ms strip travels:

0.0666 m = 66 mm

That difference directly affects cut accuracy.

9. Harmonic Frequency Modeling

Mechanical systems have natural frequencies.

Natural torsional frequency:

fn=12πKJf_n = \frac{1}{2\pi} \sqrt{\frac{K}{J}}fn​=2π1​JK​​

Where:

• K = torsional stiffness
• J = inertia

If motor excitation frequency matches fnf_nfn​:

Resonance occurs.

Effects:

• Gear noise
• Shaft fatigue
• Dimensional fluctuation

Increasing shaft diameter increases K → raises natural frequency → reduces resonance risk.

Helical gears reduce harmonic excitation vs spur gears.

10. Harmonic Chart Example (Conceptual)

If natural frequency = 22 Hz
Motor electrical frequency at certain RPM = 22 Hz

Resonance risk occurs.

Engineering solution:

• Change gear ratio
• Increase shaft stiffness
• Add damping
• Adjust motor ramp profile

11. Hydraulic Lubrication & Oil Viscosity Selection

Hydraulic oil must:

• Maintain film strength
• Resist oxidation
• Dissipate heat
• Prevent cavitation

11.1 ISO Viscosity Selection Table

Operating TemperatureRecommended ISO Grade
20–40°CISO 32
40–60°CISO 46
60–80°CISO 68
Heavy load / hot climateISO 68–100

Too low viscosity:
• Film breakdown
• Wear

Too high viscosity:
• Pump inefficiency
• Heat buildup

12. Hydraulic Cooling Engineering

Heat generated from:

• Pressure drops
• Flow restriction
• Pump inefficiency

Temperature target:

40–55°C oil temperature

Cooling methods:

• Air cooler
• Oil-water heat exchanger

Overheating causes seal degradation.

13. Integrated PBR Cutting System Example

For 36” PBR at 35 m/min:

• 250 kN hydraulic cylinder
• ISO 46 oil (moderate climate)
• Servo-driven flying shear
• 30 kW main motor
• 50:1 gearbox
• Harmonic damping via helical gears
• Blade clearance 0.05 mm

This configuration ensures:

• ±1 mm length accuracy
• Minimal burr
• Controlled dynamic load
• Reduced torsional oscillation

Final Engineering Summary

Hydraulic and cutting systems are the highest instantaneous force zones in roll forming.

They determine:

• Length accuracy
• Dynamic stability
• Gearbox lifespan
• Frame fatigue
• Profile edge quality

Servo integration, harmonic control, blade metallurgy, and oil selection must be engineered together.

Cutting is not just slicing metal.

It is a controlled energy transfer event inside a synchronized mechanical system.